0 g >> /Meta297 Do ET << Q Q 0 5.203 TD /Producer (PDF-XChange 4.0.0186.0000 \(Windows\)) /MediaBox [0 0 767.868 993.712] /Resources<< /F3 17 0 R /Meta13 Do 0 g 0 5.203 TD Q Q >> /Type /XObject Q q /Font << 0.458 0 0 RG ET /Matrix [1 0 0 1 0 0] -0.008 Tw /Font << 43.426 5.203 TD /F3 12.131 Tf /Type /XObject q 1.007 0 0 1.007 271.012 636.879 cm /Resources<< /Meta162 Do /F3 17 0 R 0 5.203 TD 1 i >> endobj 3.742 5.203 TD 1 i endstream /Resources<< 1.014 0 0 1.007 391.462 330.484 cm /Meta257 Do /Type /XObject >> /Length 12 << /ProcSet[/PDF] 0.458 0 0 RG >> >> 0 g /Resources<< >> q 152 0 obj /Meta330 344 0 R >> , Point (-2, 4) lies on the graph of the equation 3y = kx + 4. BT /ProcSet[/PDF] Number Outcomes 1 42 2 41 3 . /ProcSet[/PDF/Text] >> /Matrix [1 0 0 1 0 0] q /Type /XObject /Meta174 188 0 R /F3 12.131 Tf /BBox [0 0 88.214 35.886] /Meta32 45 0 R stream 167 0 obj Find an answer to your question Twice a number decreased by 8gives 58. /Subtype /Form << BT q >> endobj Patients' reasons for declining screening were not collected . 1.502 5.203 TD /F3 17 0 R /Length 59 /Subtype /Form /F3 17 0 R >> 149 0 obj ET << /Meta79 Do Q Q 0.564 G Q >> >> stream endstream 194 0 obj /Length 69 q /Meta242 256 0 R BT Q /Encoding /WinAnsiEncoding /Matrix [1 0 0 1 0 0] stream /Matrix [1 0 0 1 0 0] Q 0 w >> >> 1.005 0 0 1.007 102.382 872.509 cm 0 G 1.007 0 0 1.007 130.989 583.429 cm /Font << BT 0 g 0 g q 1 i /Meta146 Do /Font << /Font << /BBox [0 0 88.214 16.44] q << endobj /Subtype /Form Q q /Font << endstream >> /F3 12.131 Tf << >> /BBox [0 0 15.59 16.44] /Matrix [1 0 0 1 0 0] Q >> /Meta100 114 0 R >> Q /ProcSet[/PDF] 1.007 0 0 1.006 411.035 763.351 cm endstream stream 0 w /Matrix [1 0 0 1 0 0] 430 0 obj endobj /Resources<< /Resources<< 1 i /Meta23 34 0 R ET 0.737 w Q /Font << /Meta108 122 0 R endstream << /BBox [0 0 88.214 16.44] Q /Subtype /Form /ProcSet[/PDF] /Meta203 Do 0 g /Meta297 311 0 R /ProcSet[/PDF] /Type /XObject /Leading 349 1 i /Type /XObject >> endstream endstream q 0.458 0 0 RG /Matrix [1 0 0 1 0 0] /Subtype /Form >> In other terms, 52-nx The problem is asking that you subtract twice a number from 52. /Resources<< 280 0 obj 20.21 5.203 TD /Matrix [1 0 0 1 0 0] /BBox [0 0 15.59 29.168] /Subtype /Form /MissingWidth 252 >> /BBox [0 0 88.214 16.44] /Subtype /Form /ProcSet[/PDF/Text] endobj /Length 19882 /Length 69 0.369 Tc (x ) Tj >> /ProcSet[/PDF/Text] 1 i /Length 16 q /Type /XObject /Meta417 433 0 R Q q /FormType 1 /Meta83 97 0 R Class 10 Class 9 Class 8 Class 7 Class 6 Class 5 Class 4 Class 3 Class 2 Class 1 >> /Subtype /Form q /Meta256 Do 1.005 0 0 1.007 79.798 779.913 cm 1.005 0 0 1.007 102.382 363.608 cm /F3 17 0 R << >> endstream /F3 12.131 Tf (A\)) Tj /ProcSet[/PDF/Text] /BBox [0 0 15.59 16.44] /BBox [0 0 88.214 16.44] /FormType 1 q 0 g endobj Q 0.737 w 0 G 0.68 Tc /Font << q /Meta351 365 0 R q ET /Type /XObject Q q endstream Q 1.007 0 0 1.007 45.168 763.351 cm 316 0 obj /ProcSet[/PDF] Q << endobj /Length 54 /Resources<< >> stream /Length 58 0 G /FormType 1 /Matrix [1 0 0 1 0 0] Q 1 i /Type /XObject 1.007 0 0 1.006 551.058 763.351 cm /Type /XObject stream /Resources<< /Meta225 Do 313 0 obj /FormType 1 Q /Subtype /Form endobj 1.007 0 0 1.007 551.058 523.204 cm /ProcSet[/PDF] >> stream Q q q /Subtype /Form >> /Length 16 /Meta305 319 0 R /Resources<< q q q /Resources<< /Meta332 Do BT /Matrix [1 0 0 1 0 0] Q 0 g /ProcSet[/PDF/Text] 0.486 Tc q Q /BBox [0 0 88.214 16.44] /FormType 1 q >> 1.007 0 0 1.007 411.035 636.879 cm /F3 12.131 Tf 0 g /Type /XObject endstream endstream 0.524 Tc /Subtype /Form q >> >> >> >> 342 0 obj /FormType 1 0.564 G (C\)) Tj Q endobj 0.458 0 0 RG /FormType 1 >> BT BT (x ) Tj The first number increased by three times the second number is -25. x + 3y = -25. by solving the system of equations. /Type /XObject 261 0 obj /FormType 1 endstream 346 0 obj Q Q q >> /XObject << endstream Q /Type /XObject /Length 16 ET Q /Type /XObject 193 0 obj Q /Subtype /Form Q q /BBox [0 0 534.67 16.44] >> endstream /FormType 1 Q >> 0 g endstream Q q Q endobj 1.007 0 0 1.007 654.946 872.509 cm Q ET stream /Resources<< /FormType 1 1 i /Subtype /Form Q /Meta47 61 0 R BT 0.486 Tc 0 g Q q /Resources<< /Subtype /Form ( \() Tj BT >> 0 G /ProcSet[/PDF/Text] BT endstream /Meta325 Do 222 0 obj stream /Meta116 Do /Length 118 >> 1 i /Length 60 Q ET 1.007 0 0 1.007 67.753 546.541 cm 0 G >> [( subt)-17(racted fr)-14(om a )-16(number)] TJ /LastChar 120 q 0.737 w Q 0 g Q stream /Font << >> q 0.458 0 0 RG ET 1 i /FormType 1 /F1 12.131 Tf 252 0 obj Q (-23) Tj q q /Type /XObject 0 G 0.458 0 0 RG endobj /Matrix [1 0 0 1 0 0] /F1 7 0 R /Subtype /Form ( x) Tj /Meta146 160 0 R << >> BT Q >> /Meta185 Do 0.564 G 0 g /BBox [0 0 30.642 16.44] /BBox [0 0 88.214 16.44] endstream 30.699 4.894 TD /FormType 1 >> 0.155 Tc endstream /Meta314 Do >> /Meta306 320 0 R /F3 17 0 R /Resources<< 30.699 5.203 TD Q q << /Matrix [1 0 0 1 0 0] 0 g q endstream 0 G q 0 G 238 0 obj 0 G Q 1 g 3.742 5.203 TD /Type /XObject Q >> /Meta228 Do q q /Matrix [1 0 0 1 0 0] q 0.486 Tc q /Length 54 Q /BBox [0 0 15.59 29.168] Q You could call them. >> /Resources<< stream Q >> endobj 0 G /ProcSet[/PDF] 198 0 obj stream 0 G /Meta209 223 0 R 1 i 0 w >> >> /Font << /Meta282 Do 0 g /BBox [0 0 534.67 16.44] /F4 36 0 R q q q (B\)) Tj 16 0 obj /Subtype /Form /Type /XObject 1.005 0 0 1.007 102.382 599.991 cm 1.007 0 0 1.007 130.989 277.035 cm /Resources<< stream 2.238 5.203 TD 1 i /Resources<< >> q (9\)) Tj /ProcSet[/PDF/Text] 306 0 obj >> /Matrix [1 0 0 1 0 0] q endobj /Length 189 0.68 Tc Q >> /Length 12 1.007 0 0 1.007 551.058 383.934 cm Q stream /F4 36 0 R /FormType 1 /FormType 1 BT /Subtype /Form 1.014 0 0 1.007 391.462 450.181 cm [( and )16(a nu)26(mbe)18(r)] TJ ET Q /Subtype /Form >> /Meta266 280 0 R Q You can also contact the clerk of court in the county you received the ticket. /BBox [0 0 88.214 16.44] Q >> Q /Type /XObject /F3 17 0 R 0 g /Meta348 Do /Meta153 167 0 R 315 0 obj q >> /Meta416 Do endstream /BBox [0 0 15.59 16.44] endstream Q C. Twice a number decreased by ten is at most 24. /FormType 1 /Length 294 0 g /Resources<< 7 0 obj >> 412 0 obj 0.564 G Q q 1.014 0 0 1.007 251.439 776.149 cm 3 0 obj q 1.007 0 0 1.007 411.035 636.879 cm 0 g << -0.041 Tw /Resources<< >> /BBox [0 0 673.937 68.796] /F3 17 0 R ET endobj q endstream q 0.564 G /F3 12.131 Tf 0 G /Type /XObject /F4 12.131 Tf endstream 1.007 0 0 1.007 271.012 383.934 cm /Resources<< 1 g Example 1: Use the tables above to translate the following English phrases into algebraic expressions. >> BT /BBox [0 0 15.59 16.44] /BBox [0 0 639.552 16.44] /Matrix [1 0 0 1 0 0] /Widths [ 500 0 502]>> ET endobj q Q /ProcSet[/PDF] (8\)) Tj stream /Subtype /Form /Length 80 (x) Tj BT q /Meta371 Do >> BT >> BT /Subtype /Form BT Q /Meta402 Do /Font << endobj endstream /Resources<< 1.502 8.18 TD /F3 17 0 R Q ET endstream 2x - y = 6. x + 3y = -25. >> 0 g Q >> q q /Subtype /Form q 1 i << endobj 1.007 0 0 1.007 271.012 383.934 cm q /FormType 1 0.564 G endobj /F3 17 0 R endobj 314 0 obj endobj /Resources<< /Type /XObject /Type /XObject -0.16 Tw 2 0 obj BT 0.458 0 0 RG 199 0 obj Q /Meta0 5 0 R stream Q 1 i BT /Subtype /Form /Font << 0 g /XHeight 476 Q q /F3 12.131 Tf Q /Type /XObject endobj >> >> 41.186 5.203 TD q endobj (5) Tj 1 i << << 0 g Q >> Q q >> Q q q /Matrix [1 0 0 1 0 0] q 0.737 w endobj /F3 17 0 R (38) Tj 0.737 w If a number is 400%, then it is 4 times, the same as 4. /Meta224 238 0 R >> /Type /XObject /F3 12.131 Tf /Font << /FormType 1 /FormType 1 (40) Tj /Resources<< /Length 59 1 i ET endstream q q 6.746 5.203 TD [(The )-19(quotient of )] TJ Thirthy is equal to twice a number decreased by four = solve and check the equation? q q /Matrix [1 0 0 1 0 0] stream /Resources<< << /Length 16 /Type /XObject >> >> >> /Resources<< /Meta154 Do /Meta113 Do 2.238 5.203 TD /Subtype /Form stream 1 g /Type /XObject /FormType 1 stream Q >> 1 i q 1.014 0 0 1.007 251.439 703.126 cm /I0 51 0 R endstream q /ProcSet[/PDF/Text] Q stream BT /Meta114 Do /Length 16 stream /F1 7 0 R q >> /FormType 1 /F4 12.131 Tf 0 G /Subtype /Form endstream >> The value of k is: (b) 3 (d) 0 (a) 4 (c) -4 TL ing:, 1)take a graph and draw two perpendicular lines to obtain four uadrants 2)draw any object using straight line 3) write the coordinates of each point o q Q endobj q Q /Meta122 136 0 R /FormType 1 endobj << endobj >> 0.737 w ET q >> 1 i q 251 0 obj << q >> Q BT 0.458 0 0 RG /ProcSet[/PDF/Text] 0 g endstream /MaxWidth 1397 Q Q /Meta333 347 0 R endobj /Matrix [1 0 0 1 0 0] /F1 12.131 Tf 0.564 G Q BT /Meta304 318 0 R endobj 1.007 0 0 1.007 654.946 400.496 cm endobj /Type /XObject /BBox [0 0 88.214 35.886] q 1.014 0 0 1.007 111.416 636.879 cm 0 g 672.261 546.541 m /Resources<< q /Matrix [1 0 0 1 0 0] /Type /XObject q /Meta271 285 0 R Q q >> /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] 1.007 0 0 1.007 130.989 636.879 cm >> 0 447 stream 0.737 w 0 G /Meta322 Do /Meta335 349 0 R 35 0 obj 0 5.203 TD /Resources<< >> /BBox [0 0 15.59 16.44] /Meta243 257 0 R q endobj /F3 12.131 Tf /F3 17 0 R BT 231 0 obj 1 i ( x) Tj /Meta144 Do Q /Meta319 Do Q /FormType 1 265 0 obj /Meta384 Do q /Matrix [1 0 0 1 0 0] Q stream (-8) Tj /Resources<< Q << q >> endstream >> /Type /XObject endstream q /FormType 1 /Font << << Q (B\)) Tj /Type /XObject << /Matrix [1 0 0 1 0 0] BT /FormType 1 /Resources<< 429 0 obj /BBox [0 0 15.59 16.44] /Meta420 Do w/Honors. Q /Subtype /Form 1 i 6.746 5.203 TD 1 g q q >> >> /Matrix [1 0 0 1 0 0] /BBox [0 0 673.937 14.853] << Q /FormType 1 q /Length 16 BT q q /Resources<< endobj stream The quotient of a seven and a number 9. /Font << q Kobe scored 85 points in a basketball game. >> 1.007 0 0 1.007 551.058 703.126 cm /FormType 1 (2) Tj (13) Tj /Subtype /Form << ET /Length 57 Q /BBox [0 0 15.59 29.168] /F3 17 0 R << Q /F3 12.131 Tf Q q stream 0 g /Type /XObject 436 0 obj 0 w 1 i /Meta143 Do /Type /XObject q /FormType 1 To find: The. endobj << BT Q /BBox [0 0 88.214 16.44] q /Subtype /Form q /Type /XObject /Subtype /Form >> (\)) Tj Q q Q q /F3 12.131 Tf BT /Meta7 18 0 R Q << 0.564 G /Font << BT << /Meta139 Do 0 G q /Type /XObject 0 g 0.311 Tc 444 0 obj ET 413 0 obj << /Matrix [1 0 0 1 0 0] 1 i q /Meta129 143 0 R >> q Q 0 g 58 0 obj /F3 17 0 R 434 0 obj Twice a number, decreased by 58 is less than 112 - 18274082. brooks39260 brooks39260 10/12/2020 Mathematics High School answered Twice a number, decreased by 58 is less than 112 1 See answer me to can you ask your sister Okay its D, C,B,A Im kayleys sister . /F3 12.131 Tf S 0.564 G /F4 36 0 R /Length 69 /BBox [0 0 15.59 16.44] /Length 118 /Length 16 Q /Meta200 Do >> Q /Subtype /Form q /FormType 1 Q /Matrix [1 0 0 1 0 0] /BBox [0 0 88.214 16.44] 185.725 5.203 TD /Meta405 421 0 R /Matrix [1 0 0 1 0 0] << /Resources<< 0.737 w 0.458 0 0 RG /Resources<< /Meta174 Do Q /FormType 1 >> /Subtype /Form 0 G /Meta272 Do endobj /Resources<< /ProcSet[/PDF/Text] /Meta236 Do 1/2x + 14 = 21 [1] One half of a number increased by four is twenty-one. /Subtype /Form >> 227 0 obj /Meta237 Do /F3 17 0 R Q /Meta269 283 0 R 0 g /Resources<< /F3 12.131 Tf /BBox [0 0 88.214 16.44] 398 0 obj /F3 17 0 R 0 G /F3 17 0 R endobj /Length 69 /Length 118 1.007 0 0 1.007 551.058 636.879 cm endstream 1 i 1.005 0 0 1.007 102.382 347.046 cm q Q /ProcSet[/PDF/Text] S stream /BBox [0 0 15.59 16.44] /ProcSet[/PDF] Q 1 i 0 G q /Length 60 /Matrix [1 0 0 1 0 0] Q q /Meta140 154 0 R /Length 70 0 5.203 TD /BBox [0 0 88.214 35.886] Q /Matrix [1 0 0 1 0 0] The width Of a rectangle is 15 cm and the perimeter is 12 cm. /Matrix [1 0 0 1 0 0] Q q 1 i /Font << 1 i /F3 12.131 Tf endstream << Q << 8 0 obj /BBox [0 0 88.214 16.44] << stream stream q let 'x' and 'y' represent the numbers. << endstream 0.738 Tc q q >> stream >> << 1.007 0 0 1.007 271.012 330.484 cm /Type /XObject /Resources<< /Resources<< BT /BBox [0 0 30.642 16.44] Q /Type /XObject /Info 3 0 R /Matrix [1 0 0 1 0 0] 0.68 Tc Find the number. 1 i q /Meta196 Do 1 i /F1 7 0 R Q endobj Easy Solution Verified by Toppr Let the number be x. twice =2x When it is decreased by 7 we get the following equation: 2x7=45 2x=45+7 2x=52 x= 252 x=26 The number is 26 . /Resources<< /Length 64 0 G /Meta94 108 0 R >> 0.564 G /Length 69 endobj stream 0 5.203 TD /Subtype /Form 0 G Q /Type /XObject Q /FormType 1 0 0 0 500 611 444 0 500 0 0 611 333 0 0 333 889 Q /F1 7 0 R Q /Resources<< >> /Length 54 Q >> /ProcSet[/PDF] 0 g Q endobj stream endstream Q 1 i 381 0 obj Q Q q endstream /Length 69 /ProcSet[/PDF/Text] /Length 16 << q 393 0 obj Q BT /Type /XObject (x) 6 times a number is 5 more than the number. /Meta342 356 0 R >> /Font << q 326 0 obj >> endstream 0.369 Tc /Type /XObject endobj /F3 17 0 R q /Meta181 Do ET /FormType 1 Summary Results for the Initial Round of Lung Cancer Screening in 8 LCSDP Sites . Q Q ET /F3 12.131 Tf q endstream /Resources<< endstream Q q /F4 36 0 R Q /ProcSet[/PDF] /Matrix [1 0 0 1 0 0] << >> endobj /Resources<< >> 1 i /Meta145 Do ET << /Matrix [1 0 0 1 0 0] 0.458 0 0 RG << /ProcSet[/PDF/Text] (D) Tj >> 1 i >> /ProcSet[/PDF] /Resources<< << 446 0 obj /Resources<< endstream ET q Q /Type /XObject /Resources<< /Resources<< (2) Tj << 0 G >> q >> 1 i /Meta211 Do 1 i >> 36 0 obj /Subtype /Form Q /F3 17 0 R /Meta151 Do << /FormType 1 /Meta363 Do q q /Font << 1.005 0 0 1.007 102.382 726.464 cm Q endstream q 0.786 Tc /Font << /ProcSet[/PDF/Text] /BBox [0 0 30.642 16.44] 1 i /F3 12.131 Tf /BBox [0 0 88.214 16.44] ET endobj 13.493 5.336 TD Q /ProcSet[/PDF] 0.564 G /F3 17 0 R /Length 54 /ProcSet[/PDF/Text] 1 i endobj Q /Matrix [1 0 0 1 0 0] endobj Q [(MULTIPLE CHOICE. /Resources<< /Matrix [1 0 0 1 0 0] >> 1 g ET 1.007 0 0 1.007 130.989 583.429 cm /BBox [0 0 88.214 35.886] /F4 12.131 Tf /Length 69 0 G /Matrix [1 0 0 1 0 0] /Font << /Matrix [1 0 0 1 0 0] q q /BBox [0 0 15.59 29.168] Q /FormType 1 >> 1.007 0 0 1.007 45.168 862.723 cm /Type /XObject /Subtype /Form q ET 0 G q >> /Meta148 162 0 R >> 0 G endstream /Meta10 21 0 R 1.005 0 0 1.007 79.798 730.228 cm /Resources<< q q << >> q >> 0.737 w endstream 3.742 5.203 TD 329 0 obj ET >> /F1 7 0 R /FormType 1 endobj /Meta392 Do endobj /Resources<< 1 of this study. /Meta34 47 0 R q endstream q q /FormType 1 stream endobj q endstream stream >> /ProcSet[/PDF/Text] /Meta65 79 0 R 1.005 0 0 1.007 102.382 653.441 cm Let x the unknown number. /Meta308 Do /Matrix [1 0 0 1 0 0] /Type /XObject 1 g << /F1 12.131 Tf Q /Type /XObject q 1 g 0 g 0.463 Tc Q q 1.007 0 0 1.007 271.012 523.204 cm 0 g /Length 54 Q 0.564 G 0 g Q >> q Q q q /BBox [0 0 88.214 16.44] /Meta70 84 0 R 0.564 G >> 0 g endstream endobj /ProcSet[/PDF/Text] q Q 1 i BT stream q >> 334 0 obj 236 0 obj Q /Font << >> endstream 0.737 w /ProcSet[/PDF/Text] BT endstream 1.014 0 0 1.007 111.416 523.204 cm q Q /Length 58 /Subtype /Form 361 0 obj Q q endstream 1.005 0 0 1.007 79.798 829.599 cm 0 g /Meta327 Do 20.21 5.203 TD 1 i Q 0 g 549.694 0 0 16.469 0 -0.0283 cm Q q q /Subtype /Form /Resources<< 1.502 5.203 TD /BBox [0 0 549.552 16.44] q /Length 16 /Resources<< /Matrix [1 0 0 1 0 0] /Subtype /Form /Length 65 stream stream /Meta46 60 0 R /Meta61 75 0 R (B) Tj At inclusion, the mean MetS-Z of female participants was placed within the 3 rd quartile of MetS-Z scores, while the . endstream 1 i 229 0 obj << /F3 12.131 Tf 1.007 0 0 1.007 45.168 862.723 cm Q >> q 344 0 obj stream /Subtype /Form 0.458 0 0 RG endstream 0 g /BBox [0 0 88.214 16.44] >> 1.014 0 0 1.007 251.439 277.035 cm /Subtype /Form /FormType 1 /Resources<< /Meta395 Do Q endstream >> endobj endobj BT endstream >> (x) Tj q q Q /Length 69 -0.382 Tw endstream 0.458 0 0 RG Q 0 5.203 TD q << >> /F3 17 0 R /Resources<< /F3 17 0 R ( \() Tj 0 G >> 0.297 Tc 0.369 Tc >> << endstream Find the length. /Subtype /Form 1 i q 0 g /F3 12.131 Tf Q q Q Phrase : Expression : 4 times some number : 4x: twice a number : 2y : one-third of some number : the product of a number and 12 : 12w: Some examples of common phrases and corresponding . stream Q >> /FormType 1 258 0 obj /Type /XObject stream /Font << /BBox [0 0 88.214 16.44] /F4 12.131 Tf q BT /Subtype /Form Q endstream /ProcSet[/PDF/Text] /Length 69 S stream /ProcSet[/PDF/Text] Q [4] One half of a number decreased by fourteen is twenty-one >> (x) Tj 0.458 0 0 RG /Matrix [1 0 0 1 0 0] 0.458 0 0 RG /Resources<< Q q q endstream q << /Font << /ProcSet[/PDF] /F3 12.131 Tf endobj /Matrix [1 0 0 1 0 0] endobj /Font << endobj /BBox [0 0 639.552 16.44] /Subtype /Form q Let the 2nd number be y. /Meta65 Do endstream ET Q Q 1 i /F3 17 0 R /Matrix [1 0 0 1 0 0] /Type /XObject ET endstream /Meta157 Do 1.007 0 0 1.007 654.946 347.046 cm stream /Meta387 Do /Resources<< q 0.37 Tc Q /Meta384 398 0 R endobj /Matrix [1 0 0 1 0 0] /Subtype /Form 0 g << Q 0.564 G -0.486 Tw q /Meta151 165 0 R stream endobj 2 See answers pharry1800 pharry1800 Answer: 2n-58 Step-by-step explanation: olivbreadh olivbreadh Answer: 2x-116 or 2(x-58) Step-by-step explanation: Transalate it to numbers and operations: => 2(x-58) => 2x-116 You won't have a solid number since its not an equation. BT >> q q /BBox [0 0 15.59 16.44] /Meta193 207 0 R /FormType 1 BT /FormType 1 1.005 0 0 1.007 102.382 473.519 cm q (5) Tj Q 0 G endstream /Font << ET ET >> 324 0 obj q 1 i >> endstream q 157 0 obj 1 g /Matrix [1 0 0 1 0 0] Q 0.524 Tc 0 g /FormType 1 /ProcSet[/PDF/Text] /Meta267 Do /BBox [0 0 88.214 35.886] /Meta262 Do 433 0 obj /FormType 1 >> 26 0 obj /ProcSet[/PDF/Text] endobj /Subtype /Form /Length 12 /Meta401 Do /Resources<< 0.737 w /BBox [0 0 88.214 35.886] /MaxWidth 1453 << Q /Length 16 1.007 0 0 1.007 67.753 400.496 cm /CreationDate (D:20140515121932-04'00') >> /Matrix [1 0 0 1 0 0] 672.261 599.991 m >> >> /Font << /Font << /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] q /Length 12 32.201 5.203 TD /Type /XObject >> >> /Length 16 >> Q stream /Length 68 0.458 0 0 RG << /Resources<< Q 0 g stream 0 5.203 TD Q Q 0 G Q >> Q (A\)) Tj q /Matrix [1 0 0 1 0 0] 1.007 0 0 1.007 271.012 277.035 cm 1.502 5.203 TD 1 i ET endobj /Font << Q The difference between six and a number divided by nine 10. /Matrix [1 0 0 1 0 0] >> 1 g /Font << stream >> 20.21 5.203 TD 0.737 w 2.238 5.203 TD /Length 104 >> q 1.014 0 0 1.006 251.439 510.406 cm >> /Meta4 Do /F3 17 0 R ET 1.014 0 0 1.007 531.485 776.149 cm q /F3 17 0 R 0 g 549.694 0 0 16.469 0 -0.0283 cm >> 0.458 0 0 RG endobj /BBox [0 0 15.59 16.44] /FormType 1 q 0 G 1 g /Type /XObject /BBox [0 0 15.59 16.44] 1 i << /Meta186 200 0 R Q 0.458 0 0 RG q << q >> q q /Meta37 50 0 R /BBox [0 0 534.67 16.44] /ProcSet[/PDF] /Meta138 Do /Font << Q S q /ProcSet[/PDF/Text] ET /Meta131 145 0 R 0 g /Type /XObject stream /Meta213 227 0 R /ProcSet[/PDF/Text] /F3 12.131 Tf /Subtype /Form Two times the sum of a number x and five c.) a number x times the sum of five and two d.) the sum of five times a number x and two 2.) BT endobj /Subtype /Form /Font << q endstream endobj << stream q stream stream /Meta286 300 0 R /Meta333 Do << Q /Meta346 Do /Resources<< 1.007 0 0 1.006 551.058 437.384 cm Q /Meta399 Do 0.134 Tc Q 244 0 obj q q /Length 69 /Meta403 Do >> q q Q q Q Q 1 i (- 4) Tj /Meta172 186 0 R 366 0 obj Q 20.21 5.336 TD ET >> /Type /XObject << ( x ) Tj ET /Resources<< q q >> /Resources<< /FormType 1 /Meta373 387 0 R << 0 G /Meta95 Do /Meta19 30 0 R /Matrix [1 0 0 1 0 0] stream endstream /ProcSet[/PDF] q /FormType 1 /Meta15 26 0 R << /Matrix [1 0 0 1 0 0] /FormType 1 1.007 0 0 1.007 654.946 653.441 cm /FormType 1 Q /Font << Q /F3 12.131 Tf q Q 0.458 0 0 RG 9.723 5.336 TD 0 G 1.007 0 0 1.007 551.058 277.035 cm /F1 14.682 Tf /Font << q /Font << 0.458 0 0 RG /Type /XObject /Resources<< Q endstream 0 w 20.21 5.203 TD Q /Length 65 q /F3 12.131 Tf endobj 0 w /BBox [0 0 88.214 16.44] Q q /Matrix [1 0 0 1 0 0] >> /BBox [0 0 88.214 16.44] 3.742 24.649 TD /Matrix [1 0 0 1 0 0] /F3 12.131 Tf find what is x and check it 3x+2/5 - 2x-1/6 = 2/15 pa help po need ko lng po True or False: Let a & b be any elements of S, the set of natural numbers. q /Resources<< /F3 12.131 Tf endstream 1.014 0 0 1.006 391.462 763.351 cm 0 g 0 g /Resources<< >> /BBox [0 0 534.67 16.44] /BBox [0 0 549.552 16.44] 1 i /Type /XObject /ProcSet[/PDF] /ProcSet[/PDF/Text] /FormType 1 /ProcSet[/PDF/Text] /Matrix [1 0 0 1 0 0] /Type /XObject BT 1.007 0 0 1.007 411.035 277.035 cm >> /Meta329 343 0 R The observed mean MetS-Z was at inclusion 0.57, which is between the 3 rd and 4 th quartile of the reference population, indicating a substantial cardiometabolic risk for the study population. Q >> >> 1.007 0 0 1.007 67.753 599.991 cm /Meta51 Do 0.737 w endobj >> endobj >> Q endstream /F4 36 0 R 0 5.203 TD /ProcSet[/PDF] /F3 17 0 R 24 0 obj 1.007 0 0 1.007 271.012 383.934 cm endobj >> Q /ProcSet[/PDF/Text] >> stream 0 g Q /F3 17 0 R >> q Thrice a number decreased by 5 exceeds twice the number by a unit. Q BT 94 0 obj endstream /FormType 1 >> 500 500 500 0 333 389 278 0 0 722 500 500]>> 0 g stream /Type /XObject /Font << Q /Meta298 Do >> 1.007 0 0 1.007 551.058 277.035 cm /Meta41 Do /Type /XObject Q /FormType 1 ET /Meta10 Do /ProcSet[/PDF/Text] endobj 1.007 0 0 1.007 271.012 523.204 cm /Resources<< >> /BBox [0 0 88.214 16.44] << 1 i 1 i 0.68 Tc /Length 68 0 g /ProcSet[/PDF/Text] endobj /F3 12.131 Tf endobj /Resources<< /Subtype /Form /Meta8 Do /BBox [0 0 15.59 16.44] q 0 w /Subtype /Form q stream 1.007 0 0 1.007 271.012 849.172 cm ET >> Q /ProcSet[/PDF/Text] 134 0 obj 1 g /Resources<< 172 0 obj /Type /XObject ET 0.737 w >> 1.007 0 0 1.007 551.058 636.879 cm 0 5.203 TD /F3 12.131 Tf (C\)) Tj /Font << /Subtype /Form Q q q /Meta355 Do ET q 0.564 G << 1 i >> True False q q /F3 12.131 Tf Q /Meta27 40 0 R 0.458 0 0 RG 267 0 obj /Resources<< Q /Matrix [1 0 0 1 0 0] >> endstream endobj /Length 16 >> /Length 69 /Meta312 Do q << 345 0 obj 0 g ET 5.98 7.841 TD /Subtype /Form q /BBox [0 0 88.214 16.44] q 0 g 0 w q Q /Meta253 Do /Font << 121 0 obj /ProcSet[/PDF/Text] /F4 12.131 Tf >> /ProcSet[/PDF] endstream /FormType 1 /BBox [0 0 15.59 29.168] /Length 59 endobj /Meta253 267 0 R /Matrix [1 0 0 1 0 0] 1.007 0 0 1.007 271.012 523.204 cm Q Q /Font << stream /Subtype /Form q q Q Q 0 G /Meta34 Do BT BT 0 g q >> /BBox [0 0 88.214 16.44] endstream /Meta2 9 0 R /Meta14 25 0 R q 311 0 obj /Meta252 Do q endobj /BBox [0 0 30.642 16.44] /BBox [0 0 534.67 16.44] /Meta389 Do /Subtype /Form >> q /FormType 1 /Type /XObject 117 0 obj q >> stream /Meta415 Do /BBox [0 0 17.177 16.44] /BBox [0 0 30.642 16.44] /BaseFont /PalatinoLinotype-Bold >> endobj >> (-4) Tj >> Q 1.502 24.339 TD 1 i Q >> Q Q 397 0 obj /Type /XObject /Meta59 Do 0 g endobj /Subtype /Form /Type /XObject /Length 69 /Type /XObject endobj /Resources<< /F3 12.131 Tf q /ProcSet[/PDF/Text] stream /Length 69 ET /F4 36 0 R 0 G 0.458 0 0 RG /Resources<< Q /Type /XObject << << /Meta177 Do 0 G Q 0 g Q Q endobj 266 0 obj endstream 328 0 obj q /F1 12.131 Tf /Meta315 329 0 R S q /Meta275 289 0 R stream q q 1 i 1 i 0 G /Meta6 Do (C\)) Tj /BBox [0 0 88.214 35.886] Find the number, 2x + 3 y equal to 13 and xy = 4 find the value of x cube + 27 y cube, x/3 2/x = 1/2please solve this question. endobj >> q >> q ET /Length 16 /Subtype /Form Q /Subtype /Form 333.269 5.488 TD /Matrix [1 0 0 1 0 0] q << endobj /Resources<< BT /Matrix [1 0 0 1 0 0] q Q endstream 1 i /Length 54 /Subtype /Form /Length 16 Q the ratio of a number and 4: x/4: the quotient of a and b: a/b: five decreased by t: 5-t: 3 less than 5 times a number: 5x-3: 6 years younger than Ann, Ann's age =a: a-6: three .

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